Russian tennis player Andrei Rublev qualified for the quarterfinals of the Australian Open today, after defeating the local player, Alex de Minor, after five sets - 3:2 (6:4, 6:7, 6:7, 6:3, 6:0).
The fifth tennis player in the world won the 10th on the ATP list after four hours and 14 minutes.
He made two breaks in the first set, compared to De Minor's one break, and took the lead in the match.
In the second set, the tennis players won games on their serves and a tie-break was played, which De Minor won with 7:5.
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In the third set, the tennis players broke each other and a tie-break was played, which the Australian won 7:4.
Rubljov improved his game in the continuation, won the fourth set with three lost games, and in the decisive fifth set he did not lose a single game and after the second match point he qualified for the quarterfinals.
He will play against the Italian Janiko Siner, who earlier today defeated the Russian Karen Khachanov 6:4, 7:5, 6:3.
Bonus video:
